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2 years ago

Please help me I have no idea what I'm doing :(

Mathematics

1 answer:

tatyana61 [14]2 years ago

3 0

Answer:

x = (-b ± √b² - 4ac)/2a

Step-by-step explanation:

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For what value of x does 3^2x=9^3x-4

Andrei [34K]

Answer:

x = 2.

Step-by-step explanation:

3^2x = 9^(3x - 4)

9^3x-4 = 3^2x

(3^2)^(3x-4) = 3 ^2x

3^6x-8 = 3^2x

6x - 8 = 2x

4x = 8

x = 2 (answer).

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3 years ago

What's the reciprocal of 2 4/7 ?

Gnom [1K]

Answer:

7/18

Step-by-step explanation:

² $\frac{4}{7}$ =((2*7)+4)/7

2*7=14

14+4=18

18/7⇒7/18

4 0

3 years ago

Witch is greater -4 or 8/2

OLga [1]

8/2 is the greater one.

6 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$

6 0

3 years ago

Help l rely need it plz plz

tangare [24]

I think number 6. Is 45°

6 0

2 years ago

Please help me I have no idea what I'm doing :(​

Please help me I have no idea what I'm doing :(