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d1i1m1o1n [39]
3 years ago
11

For the most effective presentation, it's best to A. watch the projection screen to ensure there are no errors in your presentat

ion.
B. practice to the point where speaker notes aren't necessary.
C. read the slide material to the audience verbatim to ensure they understand your message clearly.
D. rely heavily on the speaker notes to ensure you cover each point.
Computers and Technology
2 answers:
ElenaW [278]3 years ago
6 0

Answer:

The answer to this question is option A and option C.

Explanation:

In the rules for effective presentation can be given as:

1) All the slides contain the shortest titles because the shortest title does not show it is wrong.

2) In the slides, we do not use small fonts and useless graphics like logos, grids, affiliations, etc.

3) For an effective presentation, we do not read the presentation straight from the slides. we must explain the thing that is written on the slide. So the option a and option c is correct.

enot [183]3 years ago
4 0
C. Being verbal n your presentation and presenting in in a certain tone can keep people from getting confused during the presentation.
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What might be some examples of Digital Citizenship Behavior?
likoan [24]

Answer:

Being nice to others and being respectful. Acting appropriately and with respect for you and others.

Explanation:

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6 0
3 years ago
Mbr and guid advantages and disadvantages
photoshop1234 [79]

Answer:

GPT does not have limitations in terms of the number of partitions. While you can have only 4 primary partitions in MBR, you can have up to 128 partitions in Windows using the GPT partition layout. GPT partition and boot data are more secure than MBR. MBR stores data in one place only.

Explanation:

I took the test

8 0
2 years ago
Part 3:<br> Please answer
Levart [38]

Answer:

a) 4 processes

b) 2 resources

c) R1: 2 instances

   R2: 2 instances

d) R2

e) R1

f) R1

g) No resource

h)  R1

i) R2

j) R2

k) No

l)No deadlock

Explanation:

You need to know that the resources that are required by the processes for completion are shown by the request edge and the resources allocated are shown by the allocation edge. And thus, we can find what resources are allocated to the process, and required for the completion accordingly. And here again, the cycle is created, and hence deadlock may or may not occur. However, we see that resources have multiple instances and get freed on time. And hence, deadlock does not occur.

Like,

P4 uses R2 and free one instance of R2.

P3 then uses one instance of R2 and free R2.

P3 then uses one instance of R3 and free R3.

P1 uses one instance of R1 and free R1 one instance

P1 then uses R2 and free R2.

P2 uses R1 and free R1.

Hence, all the processes are complete and deadlock does not occur.

3 0
3 years ago
According to many experts, how often should files be backed up?
worty [1.4K]

Should be backed up on a regular weekly bases I go daily tho
5 0
2 years ago
Read 2 more answers
Write a full class definition for a class named Averager, and containing the following members: An data member named sum of type
RUDIKE [14]

Answer:

//program in java.

import java.io.*;

class Averager {

   public static int sum;

   public static int count;    

   //constructor to initialize values

   Averager(){

       sum = 0;

       count = 0;

   }

   //Method to return Sum

   public static int getSum(){

       return sum;

   }

   //Method to add the value passed in parameter

   public static void add(int num){

       sum=sum+num;

       count=count+1;

   }

   //Method to return Count

   public static int getCount(){

       return count;

   }

   //Method to return Average

   public static double getAverage(){

//type casting is used

       return (double) sum / (double) count;

   }      

   //User Driven Input method to run the program

public static void main (String[] args)throws IOException {

    //Using BufferedReader class for reading input

    InputStreamReader x = new InputStreamReader(System.in);

    BufferedReader inp = new BufferedReader(x);

    int n;

    do{

 System.out.println("Enter your choice");

 System.out.println("1.getSum()");

 System.out.println("2.add()");

 System.out.println("3.getCount()");

 System.out.println("4.getAverage()");

 System.out.println("5.Exit");

 n=Integer.parseInt(inp.readLine());

 switch(n)

 {

     case 1 : int s = getSum();

              System.out.println("The Sum is " + s);

              break;

     case 2 : System.out.println("Enter the number to add");

              int num;

              num=Integer.parseInt(inp.readLine());

              add(num);

              break;

     case 3 : int c = getCount();

              System.out.println("The Count is " + c);

              break;

     case 4 : double avg = getAverage();

              System.out.println("The Average is " + avg);

              break;

     default : break;

 };

    }while(n!=5);

    System.out.println("Exiting");

}

}

Explanation :

Average() constructor is used for initialization. Method getSum() will return the value of sum. Method getCount() will return the count and method getAverage() will return the average. The average will be of double type. User driver input is designed to call the methods as and when required.

Input:

Enter your choice

1.getSum()

2.add()

3.getCount()

4.getAverage()

5.Exit

1

Output:

The Sum is 0

7 0
2 years ago
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