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vfiekz [6]
3 years ago
11

Whoever find the area will get brainliest i SWEAR HELPPP

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

160

Step-by-step explanation:

Have a good day!

Alex3 years ago
5 0

ok thankssssssssssss

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What is the value of x 3x 2x 55
Juli2301 [7.4K]

Answer:

25

Step-by-step explanation:

3x+2x+55=180

5x+55=180

5x=180-55

5x=125

X=125/5

X=25

So the value of X is 25

8 0
3 years ago
HELP I HAVE 10 MINUTES PLEASE GIVE ME A REAL ANSWER :
Dimas [21]

Answer:

the third one

Step-by-step explanation:

its easy

3 0
3 years ago
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Shtirlitz [24]

Answer:

?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
14 kg of apples cost $154.how much would 16kg cost
ankoles [38]
We can set up a proportion, and let x be the amount 16kg would cost: 14/154=16/x. We simplify 14/154 = 1/11. Next, we cross-multiply to get (1)(x)=(16)(11), so x=176. Therefore, 16kg of apples cost $176.
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Hope this helps!
4 0
3 years ago
Read 2 more answers
A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000
Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

p_1=X_1/n_1=494/1000=0.494

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

p_2=X_2/n_2=552/1000=0.552

The difference between proportions is (p1-p2)=-0.058.

p_d=p_1-p_2=0.494-0.552=-0.058

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0
3 years ago
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