Julie borrowed 3500 for 3years at a seven and a half simple interest rate how much interest rate is that

There are 550 people at the school carnival.

Svet_ta [14]

Answer:

70% of the people at the fair are students

165 people are on the ride

Step-by-step explanation:

In order to find a percentage, take the fraction given, 385/550, and divide the numerator, 385, and divide it by the denominator, 550. Once completing this, we get 0.7

Next, we multiply the result by 100, and get 70, thus, 385 is 70% of 550.

To find how many people 30% of 550 is, we take the percentage and put it in a fraction with the denominator being 100(changes with size of fraction like a decimal, 300 would be over a denominator of 1000)

With 30/100, we then multiply by 550 with the equation looking like this:

30/100*550/1

Once we finish multiplying(typically using a calculator, although you can do it manually) we get 165, the value of how many people are on rides out of the total 550.

4 0

3 years ago

I don't get the answer

Goshia [24]

A' is (-12, 6)
B' is (0,6)
C' is (3, -3)
D' is (-9, -3)

Hope this helps!

7 0

3 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$