I need help asap can someone explain the answer to me plz, question is how many total inches of string is aloe using

A plane flew 525 miles in 1.75 hours. Find the average speed of the plane.

ale4655 [162]

We are trying to find the average speed of the plane, which is mph, or $\dfrac{\textrm{miles}}{\textrm{hour}}$ . Using proportions, we can find the average speed of the plane in mph:

$\dfrac{525 \,\, \textrm{miles}}{1.75 \,\,\textrm{hours}} = \dfrac{x \,\, \textrm{miles}}{1 \,\,\textrm{hour}}$

Use the information from the problem to create a proportion. Remember that we are looking for mph, so we will call that $x$ .

$\dfrac{525}{1.75} \,\textrm{miles} = x \,\textrm{miles}$

Multiply the entire equation by $1 \,\textrm{hour}$

$\dfrac{525}{1.75} = 300 = x$

Divide both sides of the equation by $1 \,\textrm{mile}$ to clear both sides of the mile unit

The average speed of the plane is 300 mph.

6 0

3 years ago

Mason borrowed 1,200 from a friend to buy a new hot tub, His friend does't charge any interest and mason makes 50 payments eavh

balu736 [363]

You can identify the slope and y-intersept. The slope is 50 and the y-intercept is (0, 1200). You could also do the x-intercept, which would be the number of months passed when he pays off the debt fully. The x intercept would be (24,0)

5 0

3 years ago

7th grade math I need some help

brilliants [131]

Answer:

$33.60

Step-by-step explanation:

First we take 80% of $40.

1. $40 * 0.80 = $32

Next we take 105% of $32.

2. $32 * 1.05 = $33.60

4 0

3 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago

In a pack of skittles, 27% are red what percentage are not red?

schepotkina [342]

Answer:

12

Step-by-step explanation:

4 0

2 years ago

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