My only guess is a^2 + b^2 = c^2
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
A. 2(-2) - 3
-4 - 3
-7
b. 2(7) - 3
14 - 3
11
2(-4) - 3
-8 - 3
- 11
Answer:
The time taken by object to travel 21 ft is 1 sec
Step-by-step explanation:
The distance travel by falling object given as
d = 5 t + 16 t²
The Distance cover by object to travel = 21 ft
so , from Distance time equation
21 = 5 t + 16 t²
or, 16 t² + 5 t - 21 = 0
Or, 16 t² - 16 t +21 t - 21 = 0
Or, 16 t ( t - 1) + 21 (t - 1) = 0
Or. (t - 1) (16 t + 21) = 0
Or, (t - 1) = 0 And (16 t + 21) = 0
∴ t = 1 And t = (
)
Hence The time taken by object to travel 21 ft is 1 sec Answer
113.1in³ should be tge volume