Answer:
y = -6x + 30
Step-by-step explanation:
The inicial value you have is $30, so this will be the value of y after 0 weeks, that is, x = 0
After one week, you spend $6, so you will have y = 30 - 6 = 24 when x = 1.
With these pair of values, we can find the linear equation:
y = ax + b
for x = 0, y = 30:
30 = a*0 + b
b = 30
for x = 1, y = 24:
24 = a*1 + 30
a = 24 - 30 = -6
So, our equation is:
y = -6x + 30
To be similar ratios of the corresponding sides should be constant.
|UV|/|EO| = 8/4=2/1
|VL|/|OG| = 4/2=2/1
|LU|/|GE| = 6/3 = 2/1
So,all three corresponding pair of these triangles UVL and EOG are in proportion, so ΔUVL and ΔEOG are similar.
Because ΔUVL and ΔEOG are similar, their corresponding angles are congruent.
m∠U=m∠E
m∠V=m∠O
m∠L=m∠G.
(x•19)4=752
x would be multiplied by 19 then after it’s getting multiplied by 4.
Answer:
y = 0.5cos(4(x+π/2)) -2
Step-by-step explanation:
The centerline of the oscillation is at -2, so only the 2nd and 4th choices are viable.
The multiplier of x is computed from (2π)/period. One period is π/2, so the multiplier of x is ...
... 2π/(π/2) = 4 . . . . . matching the 2nd selection.
The horizontal offset in the second equation (π/2) is of no consequence, as it is one full period of the function.
The peak-to-peak amplitude of the oscillation is 1 unit, so the multiplier of the cosine function (which usually has a peak-to-peak value of 2 units) is 0.5. Every offered answer has that characteristic.
The appropriate choice is the 2nd one:
... y = 0.5cos(4(x+π/2)) -2
The transformation (x,y) --> (x,-y) is reflection over x axis. while the x coordinates in the image stay the same as the original, y coordinates change the sign.
Therefore coordinates of original image and final image after reflection
E - (0,3) --> E' (0,-3)
F - (2,2) --> F' (2,-2)
G - (1,1) --> G' (1,-1)
The diagram attached shows both the original image and image after reflection
