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KengaRu [80]
3 years ago
5

I wanna finish this hw but I don't know how to do it pls teach me

Mathematics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer:

y 16

Step-by-step explanation:

ad-work [718]3 years ago
4 0
The answer to this question is Y 16
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While Tina is shopping, she finds a pair of pants she wants to buy that is priced at $35 but is on sale for 60% off. What expres
zysi [14]

Answer:

35x.40=14

Step-by-step explanation:

you multply $35 by .40 because that is the remaining cost from 60%

8 0
3 years ago
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Kenny had 5/7 more trading cards than lee. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee.
svp [43]

Answer:

Step-by-step explanation:

Let X is the number of cards Kenny has

Let Y is the number of cards Lee has

1. Kenny had 5/7 more trading cards than lee, it means

X = Y + 5/7X (1)

2. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee, it means:

X + 50%X = Y +  220 (2)

So, we solve the 2 equations to find out X and Y

\left \{ {{X=Y + 5/7X} \atop {1.5X=Y +220}} \right.

<=> X = \frac{3080}{17} and Y = \frac{880}{17}

<=> X ≈181 and Y ≈ 52

6 0
2 years ago
Five times the sum of 173 and 32
Sladkaya [172]
173+32=205 , so 205 times 5 would equal 1,025 . so the answer would be 1,025 .
4 0
3 years ago
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A high school coach wants to buy new shirts for the 25 members of the track team. The coach must spend less than $300 on the shi
jeka94

Answer:

1, 3, & 5

Step-by-step explanation:

Select three options.

1. The inequality should be written as 25 s less than 300.

2. The inequality should be written as 25 s greater than 300.

3. The circle is open.

4. The circle is closed.

5. The arrow points left.

I'm guessing these are the options? If so, please mark brainliest :)

4 0
3 years ago
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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
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