Answer:
the answer would be done like this
Step-by-step explanation:
you have to get y by itself so you would need to move the x to the right of the equal sign
once you move anything to the opposite side it switches, so positive becomes negative vice versa
-3y=-x+18
you need to make sure you have positive 1 y so you would divide y by -3 to make it 1
everything else is multiplied by -3 as well
so the answer would be y=⅓x-6
Answer:
7x+6
Step-by-step explanation:
Aryana simplified the expression 3(x + 4) + 2(2x – 3). She justified her work by letting x = 3 in both the given and simplified expressions. Which is the correct simplified expression for Aryana's expression? What is the result for both expressions when x = 3?
Simplified Expression:
3(x + 4) + 2(2x – 3)
3x+12+2(2x-3)
3x+12+4x-6
7x+6
Answer:
Step-by-step explanation:

From the initial condition,

So we have that 