Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so 
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Intercept form is: y = a(x - p)(x - q)
It is given that: p = 14, q = -6, x = 14, y = 4
4 = a(14 - 12)(14 - (-6))
4 = a(2)(20)
4 = 40a


Answer: y =
(x - 14)(x + 6)
It could be? the 7 could be 7 to literally any number soooo
(8c)^2+7c
(8c)^2=64c^2
so that..
64c^2+7c
factor out c
c(64c+7)
Answer:
Step-by-step explanation:
In where my friend
Mark me as brainliest