From the standard normal tables, obtain
P(z<1.95) = 0.9744
P(z<0.37) = 0.6443
P(z<1.32) = 0.9066
P(z<1.82) = 0.9656
P(z<1.05) = 0.8531
P(z<2.05) = 0.9798
P(z<0.03) = 0.5120
P(z<0.53) = 0.7019
Answers:
Range of z Area
-------------- ---------------------------------------
a. 0 - 1.95 0.9744
b. 0 - 0.37 0.6443
c. 1.32 - 1.82 0.9656 - 0.9066 = 0.0590
d. 1.05 - 2.05 0.9798 - 0.8531 = 0.1267
e. 0.03 - 0.53 0.7019 - 0.5120 = 0.1899
E(x) = 10x - 30
the y int is -30........that means her expenses for the week was $ 30
Answer:
8.9 i think
Step-by-step explanation:
By solving a linear equation, we conclude that you bought 4 buns and 5 cakes.
<h3>
How many of each did I buy?</h3>
We will define the two variables:
- x = number of buns bought.
- y = number of cakes bought.
We know that you spent exactly £4.35, then we only need to solve the linear equation:
x*0.40 + y*0.55 = 4.35
We need to solve that equation for x and y, such that the values of x and y can only be positive whole numbers.
We can rewrite the equation as:
y*0.55 = 4.35 - x*0.40
y = (4.35 - x*0.40)/0.55
Now we only need to evaluate it in different values of x, and see for which value of x, the outcome y is also a whole number.
We will see that for x = 4, we have:
y = (4.35 - 4*0.40)/0.55 = 5
So you bought 4 buns and 5 cakes.
If you want to learn more about linear equations:
brainly.com/question/1884491
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The value of 4 in 475 is 4 hundred
