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natka813 [3]
3 years ago
8

Christine has $90 in a savings account. The interest rate is 5%, compounded annually.

Mathematics
1 answer:
alex41 [277]3 years ago
4 0

Answer: $13.5

Step-by-step explanation:

90 x 5% = 4.5 x 3 = 13.5

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Please help! <br><br> Solve for M.<br> R=9/5M+21
ElenaW [278]

Answer:

The answer should be M = 5/9(R - 21)

Step-by-step explanation:

To find this value, follow the order of operations to isolate M.

R = 9/5M + 21

R - 21 = 9/5M

5/9(R - 21) = M

8 0
3 years ago
Find the surface area of the prism
TiliK225 [7]

Answer:

120 inches

Step-by-step explanation:

you can find it by multiplying the base x height if the base is 8 in and the height is 15 in then your answer will be

3 0
3 years ago
Solve this linear equation <br> 2(x+6)&lt;3x+8
FinnZ [79.3K]

Answer:

x > 4

Step-by-step explanation:

Given

2(x + 6) < 3x + 8 ← distribute left side

2x + 12 < 3x + 8 ( subtract 3x from both sides )

- x + 12 < 8 ( subtract 12 from both sides )

- x < - 4

Multiply both sides by - 1, reversing the symbol as a result of multiplying by a negative quantity.

x > 4

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> What is [100(−4)^n-1} equal to?
nikklg [1K]

Answer:   -5100

<u>Step-by-step explanation:</u>

\sum^4_1[100(-4)^{n-1}]\qquad \rightarrow \qquad a_1=100\ \text{and r = -4}\\\\\\S_n=\dfrac{a_1(1-r^n)}{1-r}\\\\\\\\S_4=\dfrac{100(1-(-4)^4)}{1-(-4)}\\\\\\.\quad=\dfrac{100(1-256)}{1+4}\\\\\\.\quad=\dfrac{100(-255)}{5}\\\\.\quad=20(-255)\\\\.\quad=-5100\\

3 0
3 years ago
A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
4 years ago
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