The angular frequency in rev/s of the combination when they start rotating together is 1.8 rev/s.
Apply conservation of angular momentum:
Ii.ωi=If.ωf
⇒ 1/2mR² ×3.0=( 1/2mR²+m(2R)²/12)ωf
⇒ωf =1.8rev/s.
A scalar representation of rotation rate in physics is called angular frequency, or "". It speaks of the angular displacement per unit of time, the rate of change of a sinusoidal waveform's phase, or the rate of change of the sine function's argument. The difference between angular frequency (measured in radians per second) and frequency (measured in cycles per second, also known as Hz) is two. Instead of the letter f, the symbol for frequency in this figure is. an axis-centered rotating sphere. Points further from the axis move more quickly, fulfilling = v / r. Angular frequency (), also referred to as radial or circular frequency, calculates the amount of angular momentum per unit of time. Therefore, it is measured in degrees (or radians) per second.
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Answer:
The volume of water displaced the same as the volume of the block.
Explanation:
With respect to the principle of floatation, when an object floats in a fluid; its weight is the same as the volume of the fluid displaced.
The volume of the block relates to is dimension and size which can be compared with the volume of the fluid displaced. When the block is floats in water, it would displace a reasonable volume of water. Thus, it would be expected that the volume of water displaced by the block is equal to the volume of the block.
Answer:
The potential difference at the customer's house is 117.1 V.
Explanation:
a) The potential difference at the customer's house can be calculated as follows:
<u>Where</u>:
: is the potential difference at the customer's house
: is the potential difference from the main power lines = 120 V
: is the potential difference from the lines
The resistance, R, is:
Now, the potential difference at the customer's house is:
Therefore, the potential difference at the customer's house is 117.1 V.
I hope it helps you!
b. The guitar represents half of the wave length. So the full wave length is 2x0.9m = 1.8m.
Using the given equation, v= λ ∙ f,
the wave is moving back and forth along the string at 1.8 ∙ 256
= 460.8m/s
c. Sound waves travel at 6,000 m/s.
Using the given equation, v=d/t, or d=vt,
train's vibration in 3 seconds travels 6000*3
=18,000m or 18km