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Evgen [1.6K]
3 years ago
10

Equations to use: v= λ ∙ f v=d/t

Physics
2 answers:
Monica [59]3 years ago
8 0

b. 460.8 m/s

Explanation:

We have a stringth with length L = 0.90 m, and a standing wave with frequency f = 256 Hz. The equation that relates the speed of the wave with the frequency and the length of the string is

f=\frac{v}{2L}

where v is the speed of the wave. Re-arranging the equation and putting in the numbers, we find:

v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s

c. 18,000 m

Explanation:

The speed of the sound wave in steel is v = 6000 m/s. The train's vibration travels for 3 seconds, so the distance covered by the sound wave during this time can be calculated using the formula

v=\frac{d}{t}

Re-arranging the equation and substituting the numbers, we can find d:

d=vt=(6000 m/s)(3 s)=18,000 m

Anna71 [15]3 years ago
6 0

b. The guitar represents half of the wave length. So the full wave length is 2x0.9m = 1.8m.

Using the given equation, v= λ ∙ f,

the wave is moving back and forth along the string at 1.8 ∙ 256

= 460.8m/s

c. Sound waves travel at 6,000 m/s.

Using the given equation, v=d/t, or d=vt,

train's vibration in 3 seconds travels 6000*3

=18,000m or 18km

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Piaget used a pendulum apparatus to assess whether children had reached the _____ stage of cognitive development.
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You are given two vectors vector A = 4.9 at 31o vector B = 6 at 156o Angles are measured counterclockwise from the x-axis. What
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Answer:

   C_{y} = 4.96  and     θ' = 104,5º

Explanation:

To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.

Let's start by decomposing the two vectors.

Vector A

             sin θ = A_{y} / A

             cos θ = Aₓ / A

             A_{y} = A sin  θ

             Ax = A cos θ

             A_{y} = 4.9 sin 31 = 2.52

             Ax = 4.9 cos 31 = 4.20

Vector B

           B_{y} = B sin θ

           Bx = B cos θ

           B_{y} = 6 sin 156 = 2.44

           Bx = 6 cos 156 = -5.48

The components of the resulting vector are

X axis

         Cx = Ax + B x

         Cx = 4.20 -5.48

         Cx = -1.28

Axis y

         C_{y} = Ay + By

         C_{y} = 2.52 + 2.44  

         C_{y} = 4.96

Let's use the Pythagorean theorem to find modulo

         C = √ (Cₙ²x2 + Cy2)

         C = Ra (1.28 2 + 4.96 2)

         C = 5.12

We use trigonemetry to find the angle

         tan θ = C_{y} / Cₓ

          θ’ = tan⁻¹ (4.96 / (1.28))

           θ’ = 75.5

como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es

       θ’ = 180 – tes

        θ‘= 180 – 75,5

        θ' = 104,5º

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