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musickatia [10]
3 years ago
14

What is the perpendicular slope intercept form plss??​

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0

Answer: first put the equation of the line given into slope intercept form by solving for why you get why equals negative 2X +5 so the slope is negative to perpendicular lines have a opposite reciprocal slopes so the slope of the line we want to find is 1/2 plugging in the point given to the equation why equals 1/2 X plus B and solving Furby we get B equals six

Step-by-step explanation:

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Find the area of a triangle with vertices at D(2, 0), E(–1, 0), and F(2, –7).
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Im suck on the same question 
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Which angles are adjacent angles to 3? Select all that apply
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Two Answers: Angle 1, Angle 4

Adjacent angles share a common segment, line, or ray. Think of two adjacent rooms sharing a common wall.

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Rectangle 1 has length 10 and width 20. Rectangle 2 is made by multiplying each dimension of Rectangle 1 by a factor of k=3
Gwar [14]

Answer:

30cm, 60cm

Step-by-step explanation:

Given data

Dimensions of the first rectangle

Length =10cm

Width =20cm

We are told that the dimensions of the second rectangle is gotten by multiplying the first rectangle by 3

Hence the dimensions of the second rectangle is

Length =10*3= 30cm

Width = 20*3= 60cm

5 0
3 years ago
A 'snail's pace is 60 inches per minute. At this rate how long will it take the snail to crawl 120 feet?
True [87]
Ok, so here, we have the unit rate of the snail. Now, we need to set up a proportion.

60/1 = 120/x

Now, cross multiply.

60*x = 120*1

60x= 120

Now divide to solve for x.

60x/60 = 120/60
x = 120/60 
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Now our final answer is 2.

Final answer:- The snail will take 2 minutes to crawl 120 feet

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3 years ago
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A sanitation department is interested in estimating the mean amount of garbage per bin for all bins in the city. In a random sam
soldi70 [24.7K]

Answer:

a) 52.8-2.02\frac{3.9}{\sqrt{40}}=51.554    

b) 52.8+2.02\frac{3.9}{\sqrt{40}}=54.046    

c) 52.8-2.71\frac{3.9}{\sqrt{40}}=51.129  

d) 52.8+2.71\frac{3.9}{\sqrt{40}}=54.471  

e) Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =52.8 represent the sample mean for the sample

\mu population mean (variable of interest)

s=3.9 represent the sample standard deviation

n=40 represent the sample size  

a) What is the lower limit of the 95% interval? Give your answer to three decimal places

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,39)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

52.8-2.02\frac{3.9}{\sqrt{40}}=51.554    

b) What is the upper limit of the 95% interval? Give your answer to three decimal places

52.8+2.02\frac{3.9}{\sqrt{40}}=54.046    

So on this case the 95% confidence interval would be given by (51.554;54.046)    

c) What is the lower limit of the 99% interval? Give your answer to three decimal places

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,39)".And we see that t_{\alpha/2}=2.71

Now we have everything in order to replace into formula (1):

52.8-2.71\frac{3.9}{\sqrt{40}}=51.129  

d) What is the upper limit of the 99% interval? Give your answer to three decimal places

52.8+2.71\frac{3.9}{\sqrt{40}}=54.471  

So on this case the 99% confidence interval would be given by (51.129;54.471)    

e) Consider the claim that the mean amount of garbage per bin is 54.1985 pounds. Is the following statement true or false? The decision about the claim would depend on whether we use a 95% or 99% confidence interval: True/False

Yes, depends of the confidence level.

At 95 % of confidence the value 54.1985 pounds is not included on the interval. At 5% of significance the statement is FALSE.

At 99 % of confidence the value 54.1985 pounds is included on the interval. So at 1% of significance the statement is TRUE.

3 0
4 years ago
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