I can't see pictures T^T.
To find the are of a triangle, you multiply the dimensions as you would a rectangle, but divide the product by 2.
Example:
The dimensions of triangle B are 4 and 9.
4x9=36
Now divide.
36/2=18
So the area of triangle B is 18.
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hope it helps
Answer:
<h2>A= πr^2/4</h2>
Step-by-step explanation:
Step one:
given data
diameter of circle= 12 in
the radius is r=d/2=6in
the area of the circle is
A=πr^2
A=3.142*6^2
A=3.142*36
A=113.1in^2
If the circle is folded in half, the area will be A/2= 113.1/2= 56.55in^2
In the corresponding shape is folded again the area is A/4= 28.3in^2
<u>The expression for the last shape is </u>
<u>A= πr^2/4</u>
Answer:
The circle on the far left is the sum of 4x + 3y and 2x - y so the answer is 4x + 3y + 2x - y = 6x + 2y. The circle on the far left is the sum of x + 4y and something. To find that "something" we can do 4x + 5y - (x + 4y) = 3x + y which is the value of the bottom right rectangle. This means that the value of the bottom circle is 2x - y + 3x + y = 5x.
Answer:
4x cm.
Step-by-step explanation:
Suares have to have all 4 sides equal. The area of the rectangle (2x8) is 16.
16/4 = 4, so the square has sides of 4cm each to equal an are of 16. (4x4=16)
Area = 7(x + 2) = 7x + 14
Perimeter = 2(7 + x + 2) = 2(9 + x) = 18 + 2x
7x + 14 > 18 + 2x
7x - 2x > 18 - 14
5x > 4
x > 4/5
