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Verdich [7]
3 years ago
15

What is the domain and range of the step function with the equation below f(x)=-3 x

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0
The function f(x)=-3x follows a linear form y=ax+b, where a is the slope and b is the y-intercept. From our function:
f(x)=-3x
f(x)=-3x+0
slope, a=-3 and y-intercept is 0. This implies that the function is a linear function, thus the domain and range will be:
domain:
(-∞,∞)

Range:
(-∞,∞)
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Which numbers are 9 units from −5 on this number line?
Luba_88 [7]

Answer:

-14 and 4

Step-by-step explanation:

add and subtract 9 from -5

8 0
3 years ago
What number am I?
Katyanochek1 [597]

Answer:

The numbers less that 40 which have sum of digits 8 are 17, 26, 35.

Only one of those that has a factor of 7. And that is 35.

So you are 35.

Second way:

The numbers less that 40 which have a factor of 7 are 7,14,21,28,35

Only one of those which has sum of digits as 8. And that is 35.

So you are 35.

Step-by-step explanation:

3 0
2 years ago
5/8-11/20=?<br><br> Help what’s the answer I’m stuck on finding the LCM of the denominators
zhannawk [14.2K]

Answer:

3/40

Step-by-step explanation:

  • \frac{5}{8} - \frac{11}{20}
  • \frac{25}{40} - \frac{22}{40} (LCM is 40)
  • \frac{25-22}{40}
  • \frac{3}{40}

Therefore, the answer is 3/40!

4 0
2 years ago
5•1000000 is how many times as large as 5•10000
gizmo_the_mogwai [7]

Answer:

100 times

Step-by-step explanation:

<em>5•1000000</em> has 2 more zeros than <em>5•10000 </em>so that means the first number is 100 times larger than the second number! hope this helps and please mark as brainiest

3 0
2 years ago
Read 2 more answers
Simplify: log81/8 + 2log2/3 - 3log 3/2 +log 3/4​
MissTica

Answer:

0.

Step-by-step explanation:

Using the laws of logarithms:

log81/8 + 2log2/3 - 3log 3/2 + log 3/4​

= log 81/8 + log (2/3)^2 - log (3/2)^3 + log 3/4

= log 81/8 + log 4/9 - log 27/8 + log 3/4

= log 81/8 + log 4/9 - (log 27/8 - log 3/4)

= log (81/8 *  4/9) - log (27/8 * 4/3)

= log 9/2 - log 9/2

= 0.

5 0
3 years ago
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