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alisha [4.7K]
3 years ago
12

A police car drives 108km in 1 1/2 hours what is its average speed in kilometers per hour.

Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

ANSWER

72km/h

EXPLANATION

The average speed of the car can be calculated using the formula:

Average Speed=total distance/ total time taken.

The car covers a distance of 108km in 1½ hours.

We substitute the values into the formula to obtain,

Average  \:  \: Speed= \frac{108}{1.5}

Average  \:  \: Speed=72 {kmh}^{ - 1}

Therefore the average speed of the journey is 72km/h

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Nesterboy [21]

Answer:

26

Step-by-step explanation:

[(7+3)5-4]/2+3

-To solve this equation you have to use PEMDAS

P- Parentheses

E- Exponents

M- Multiplication

D- Division

A- Addition

S- Subtraction-

- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])

Step 1) [(10)5-4]/2+3

- First you do "P," parentheses, so you add 7+3=10

Step 2) [50-4]/2+3

- Next you do "M," multiplication, and multiply 10x5=50

Step 3) [46]/2+3

- Then you do "S," subtraction, and subtract 50-4=46

(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)

Step 4) 23+3

- Now we do "D," division, and divide 46/2=23

Step 5) 23+3=6

- Finally we do "A," addition, and add 23+3=26 so the answer is 26

(FYI: "/" means division)

4 0
2 years ago
Find the measure of each angle. a. Angle A = ? b. Angle B = ? c. Angle C = ?
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Answer:

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angle C=60

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3 years ago
Edward is taking a trip. The distance
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Answer:

67.5 miles

Step-by-step explanation:

If 1 cm represents 15 miles, then 4.5 cm represents 4.5 * 15 miles.

4.5 * 15 miles = 67.5 miles

Answer: 67.5 miles

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Step-by-step explanation: I hope this helps

You would have to estimate this to about 930 if to the nearest integer. <3

5 0
3 years ago
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Answer:

A product of factors is zero if and only if one or more of the factors is zero.  That is, if ab = 0, then either a = 0 or b = 0 (or both).

Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both.  (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.

Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.

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3 years ago
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