Don’t worry this is pretty easy :)
The answer is -
50% recessive alleles
50% dominate alleles
explication- find out what alleles you’re working with (heterogeneous and homogeneous)
[heterogeneous is 1 dominant and 1 recessive- homogeneous is 2 of the same alleles they can be dominant or recessive]
We’re working with a parent with heterogeneous and another parent with recessive homogeneous.
draw a allele chart
__
|_|_|
|_|_|
they look like this and take your first parents alleles and put them at the top
L s
_ _
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it should look like this, then take your parent with both recessive and put them vertical to the box
L s
_ _
s |_|_|
s |_|_|
it should look like this, now you drag one letter down and one letter across for each box
L s
__ __
s|Ls|ss |
s|Ls|ss |
— —
it’s should look like this when they’re done, i think you’re doing a grade below me in biology so the ratio should be 50/50 for both phenotype and genotype.
TRY TO LEARN THE VOCABULARY IT HELPS A LOT AND BASICALLY TELLS YOU THE ANSWERS!
GOOD LUCK :)
Answer:
A subunit of Rubisco takes approximately 0.33 s to perform one reaction
Explanation:
The kcat it's a kinetic first order constant that related the properties of the enzyme substrate complexes in a mechanisms and represents the overall first order process of the transformation of the substrate-enzyme complex into product.
Also kcat can be seen as the turnover number of an enzyme, representing the maximum number of substrate molecules that the enzyme can transform into product per time unit and per active site.
If the kcat is 3 s^-1, it means Rubisco can catalyse the transformation of 3 substrate molecules per second.
So, the time that takes a single reaction, should be the inverse of kcat.
To see it more clearly, the time needed for a single reaction is the time observed divided by the number of reactions done during that time.
In other words:
3 reactions ----------- 1 s
1 reaction -------------- x
- x=1 reaction/3 reactions.s^-1 = 1/kcat = 1/3 s ~ 0.33 s
So the time that takes one Rubisco subunit to do one reaction is approximately 0.33 s
Answer:
the addition of solutes lowers the potential, while an increase in pressure increases the potential.
Explanation:
Double layered nuclear, the outer nuclear membrane is continuous with the membrane of the rough endoplasmic reticulum (ER), it also continues with the inner nuclear membranes since the two layers are fused together at a numerous tiny holes called nuclear pores that perforate the nuclear enevelope