Answer:
Greatest sack = 42
1 candy bar and 3 lollipops
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Step-by-step explanation:
Represent Candy bars with C and Lollipops with L


Solving (a): Greatest number of treat sacks
To solve this, we simply calculate the GCF of C and L


Hence, the GCF is


Hence, greatest number of sack is 42
Solving (b): Number of treat in each sack.
To do this, we simply divide the number of C and L by the calculated GCF
For C:



For L:



<em>Hence, 1 candy bar and 3 lollipops</em>
Answer:
technically only 10 but if you round up then its 11.
Step-by-step explanation:
97 divided by 15 ~6.47
71 divided by 6.47~ 10.97
Let the number of chairs Gavin build per week is x and number of tables he builds per week is y.
It takes 4 hours to work on a chair and 10 hours to work on a table. So time taken to work on x chairs and y tables will be:

Gavin wants to work for no more than 40 hours. So we can write the inequality as:

It takes $10 worth of supplies to build a chair and $15 worth of supplies to build a table. So cost or worth of supplies for x chairs and y tables will be:

Gavin wants to spend no more than $80 on material. So we can write the inequality as:

Thus the system of inequalities is:


We can observe the possible combinations from the graph of these inequalities, which is shown below:
a) 0 chair and 3 tables
b) 5 chairs and 2 tables
c) 8 chairs and 2 tables
Answer:
1= 6 2/3 2= 4 13/30 3= 20 3/16
Step-by-step explanation:
1: Convert into improper fraction: 16/3 * 5/4
Common Factor =4 so 4/3 * 5/1
Multiply = 4*5 and 3*1
Answer: 20/3 = 6 2/3
2: Convert into improper fraction: 7/5 * 19/6
Multiply: 7*19 and 5*6
Answer: 133/30 = 4 13/30
3: Convert into improper fraction: 57/8 * 17/6
Common factor =3 = 19/8 * 17/2
Multiply: 19*17 and 8*2
Answer: 323/16 = 20 3/16