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nadya68 [22]
3 years ago
5

Write using no denominator. (No fraction line is necessary. Use x for multiplication between numbers.)

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0
If you don't want to express this into fractions, then you take the inverse of the exponents in your denominator. For example, 8 would be 8^-1, x^4 would be x^-4, y^3 would be y^-3 and z would be z^-1. Then, just multiply all of them. The final answer would be

3 x 8^-1 x a²b³c^5x^-4y^-3z^-1

I hope my explanation helped you understood the solution :)
nydimaria [60]3 years ago
3 0

Answer:

\large\boxed{3\times8^{-1}\times a^2b^3c^5x^{-4}y^{-3}z^{-1}}

Step-by-step explanation:

\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{3a^2b^3c^5}{8x^4y^3z}=3a^2b^3c^5\times\dfrac{1}{8x^4y^3z}\\\\=3a^2b^3c^5\times8^{-1}x^{-4}y^{-3}z^{-1}\\\\=3\times8^{-1}\times a^2b^3c^5x^{-4}y^{-3}z^{-1}

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Each sequence has eight terms. Evaluate each related series. 1,-1,-3, . . . . . . -13
o-na [289]

The sum of the 8 terms of the series 1-1-3-5- ... -13 is -48

The given sequence is:

1,-1,-3,  . . -13

and there are 8 terms.

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Notice that the series is an arithmetic series with:

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common difference, d = -1 - (1) = -2

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To find the sum of the series, use the sum formula:

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Substitute n = 8, a(1) = 1, a(n) = a(8) = -13 into the formula:

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Learn more about sum of a series here:

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1 year ago
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hope this helps

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2 years ago
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