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3 years ago

Write using no denominator. (No fraction line is necessary. Use x for multiplication between numbers.)

Mathematics

2 answers:

Wewaii [24]3 years ago

7 0

If you don't want to express this into fractions, then you take the inverse of the exponents in your denominator. For example, 8 would be 8^-1, x^4 would be x^-4, y^3 would be y^-3 and z would be z^-1. Then, just multiply all of them. The final answer would be

3 x 8^-1 x a²b³c^5x^-4y^-3z^-1

I hope my explanation helped you understood the solution :)

nydimaria [60]3 years ago

3 0

Answer:

$\large\boxed{3\times8^{-1}\times a^2b^3c^5x^{-4}y^{-3}z^{-1}}$

Step-by-step explanation:

$\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{3a^2b^3c^5}{8x^4y^3z}=3a^2b^3c^5\times\dfrac{1}{8x^4y^3z}\\\\=3a^2b^3c^5\times8^{-1}x^{-4}y^{-3}z^{-1}\\\\=3\times8^{-1}\times a^2b^3c^5x^{-4}y^{-3}z^{-1}$

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HELP ASAP TIMED!!!!!!!!!!!!!!!!!!!!!!!

pochemuha

Answer:

Step-by-step explanation I think a

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3 years ago

(–6)² – (–7)² I need a step by step process.

Sati [7]

Is the = -13. Is the response

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3 years ago

karen amad an hans have a total of 113 in their wallets? if hans has 4 times the amount of karen an karen has 7 dollars more tha

zvonat [6]

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

Solution:

Let "h" be the amount in Han's wallet

Let "k" be the amount in karen wallet

Let "a" be the amount in amad wallet

They have a total of 113 in their wallet

Therefore,

h + k +a = 113 ------- eqn 1

If hans has 4 times the amount of karen

Amount with Han = 4 times the amount with Karen

h = 4k ------- eqn 2

And karen has 7 dollars more than amad

k = 7 + a

a = k - 7 ---------- eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

4k + k + k - 7 = 113

6k - 7 = 113

6k = 113 + 7

6k = 120

k = 20

Substitute k = 20 in eqn 3

a = 20 - 7

a = 13

Substitute k = 20 in eqn 2

h = 4k = 4(20) = 80

h = 80

Summarizing the results:

Amount in Han wallet = $ 80

Amount in amad wallet = $ 13

Amount in karen wallet = $ 20

6 0

3 years ago

The exponential model A=429e 0.024t describes the population, A, of a country in millions, t years after 2003. Use the model t

d1i1m1o1n [39]

Answer:

Year 2,590

Step-by-step explanation:

In this question, we are asked to calculate the year at which the population of a country will be a certain amount given the exponential equation through which the equation proceeds.

Let’s rewrite the exponential function;

A = 429e^0.024t

Now here, our A is 559,000,000

t is unknown

Let’s substitute this value of A in the exponential equation;

559,000,000 = 429 * e^0.024t

559,000,000/429 = e^0.024t

1,303,030.303030303 = e^0.024t

Let’s take the logarithm of both sides to base e, we have;

ln(1,303,030.303030303) = ln(e^0.024t)

14.08 = 0.024t

t = 14.08/0.024

t = 587 years

Now, we add this to year 2003 and this gives year 2590

7 0

3 years ago

A store has two different sizes of ice cream the smaller container cost 3.87 for 48 ounces the larger container cost 6.42 which

elena-14-01-66 [18.8K]

Consider the complete question is "A store has two different sizes of ice cream on sale this week. The smaller container costs $3.87 for 48 ounces. The larger container costs $6.42 for 128 ounces. which ice cream costs less per ounce?"

Given:

The smaller container costs $3.87 for 48 ounces.

The larger container costs $6.42 for 128 ounces.

To find:

Which ice cream costs less per ounce?

Solution:

We know that

$\text{Cost per ounce}=\dfrac{\text{Total cost}}{\text{Number of ounces}}$