The correct options are:
A. The scatter plot has an outlier at (15, 2)
B. The scatter plot has a cluster with a range from 2 to 4
<u><em>Explanation</em></u>
Co ordinate of any point can be written in form of (x,y) where first value is the distance across x-axis and second value is the distance across y-axis.
We can see in the plot, that the outlier point is 15 unit across x-axis and then 2 unit across y axis from the origin. So the co ordinate of that point will be (15, 2).
Range means the values across the y-axis. We can see that the cluster starts at y=2 and ends at y=4. That means, the scatter plot has a cluster with a range from 2 to 4.
To find the angle use arc tan (-5/-7) which simplifies tips arctan(5/7). arc tan is tan to the power -1, which is also called inverse tan. The heading of the angle, if you drew this out on a graph your angle would be in the third quadrant and therefore the heading is south of west.
Yes it would be 8/15 the adjacent is always on the bottom and opposite is always on the side not the leaning side but the straight side
5 1/7 x 1/9= 36/7 ×1/9= 4/7
8-3/2= 8-1 1/2= 7 1/2
Answer:
B. g(x) is shifted 5 units right and 2 units up from f(x).