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Lemur [1.5K]
3 years ago
8

How do you complete the square of x^2-14x+33=0?

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0
X² - 14x + 33 = 0 is in the form ax² + bx + c = 0. We will need this for the second step.

Subtract 33 from both sides
x² - 14x = - 33

Divide the b term by 2 and then square the result. Then add that to both sides.
- 14 / 2 is - 7. (- 7)² = 49. Add that to both sides

x² - 14x + 49 = - 33 + 49

Combine the constants and factor the trinomial
(x - 7)² = 16

Square root both sides
x - 7 = +/- 4
or
x - 7 = - 4 and x - 7 = 4

You have to place a plus-minus statement because (- 4)² and 4² both equal 16. 

Now we solve for x in each equation. Add 7 to both sides to isolate our variable.
x = 3 and x = 11

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3 years ago
Can anyone help me with dis
dolphi86 [110]

Answer:

Slope is 2.

Step-by-step explanation:

So to find slope, we need to take the change in the y value, and the change in the x value, and then divide them. This may be confusing, so here is just 3 formulas in 3 seperate steps that we use to find it:

Step 1 - x_2-x_1=change_.in_.x

Step 2 - y_2-y_1=Change_.in_.y

Step 3 - \frac{Change_. in_. y}{Change_.in_.x}=slope

So lets start by doing step one.

All we need is to look for two x values. Lets use 5 and 6:

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So 1 is our change of x. This is our 1st step.

Next we can use 2 y values, note that these should be the 2 y values that go wiht the x values above. So this means we have to use -3 and -1:

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So 2 is our change in y. This is our 2nd step.

Now lets plug this into:

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7 0
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Answer:

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