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4 years ago

How do you complete the square of x^2-14x+33=0?

1 answer:

7 0

X² - 14x + 33 = 0 is in the form ax² + bx + c = 0. We will need this for the second step.

Subtract 33 from both sides
x² - 14x = - 33

Divide the b term by 2 and then square the result. Then add that to both sides.
- 14 / 2 is - 7. (- 7)² = 49. Add that to both sides

x² - 14x + 49 = - 33 + 49

Combine the constants and factor the trinomial
(x - 7)² = 16

Square root both sides
x - 7 = +/- 4
or
x - 7 = - 4 and x - 7 = 4

You have to place a plus-minus statement because (- 4)² and 4² both equal 16.

Now we solve for x in each equation. Add 7 to both sides to isolate our variable.
x = 3 and x = 11

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Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

Please help quickly :) thanks

juin [17]

The missing part is the proof ... hope it helped thank you you welcome have a frat day thanks bye adios amigo q to balls bin en too visa much's gracious yew me la peals pot too Ajax thanks yes what ever loll

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3 years ago

Consider he following expression.

Feliz [49]

What a mysterious expression you have there!

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3 years ago

Can someone help me ?

Scrat [10]

Answer:

Equation: -2x = -6

Solution: x = 3

Step-by-step explanation:

1. Take a look at the diagram. With two -x on one side and 6 of the -1 on the other, we can see the equation to be -x - x = -1 - 1 - 1 - 1 - 1 - 1

2. However, this is not a proper equation as it is not simplified: - 2x = -6

3. Now that we have the equation, apply simple algebra to recieve x, as such:

-2x = -6 ⇒ x = -6/-2 ⇒ x = 6/2 ⇒ x = 3

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Answer:

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