<span>2/3 (x-7)= -2
x - 7 = -2 * 3/2
x - 7 = -3
x = -3 + 7
x = 4</span>
Divide 6 by 1/3. I don't know what you are asking.
Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
1
∫ f(x) dx = x⁵/5 + 3x⁴/4 - 5x³/3
-1
[1⁵/5 + 3⁴/4 - 5³/3] - [ -1⁵/5 -3⁴/4 +5³/3]
plug that into your calculator and that's your rate of change
I believe the diagonals would be perpendicular. So if it's on a graph/coordinate plane the slopes would be opposite. And all the sides would be the same length/2 sets are parallel/same slope
