Look for a common number in all the terms
6(2a+3b-c)
Answer:
the answer is 8.5
Step-by-step explanation:
divide 85 by 10 to get 8.5 for all the dimension
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:
log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)
log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)
simplifying by writing log9 = 2log3 and log6 = log2+log3
x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) =
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)
So 6^x = 4/9
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
