Answer:
seconds
-----------------------------------------------------------
-----------------------------------------------------------
With conversion fractions, the denominator unit is always what you want to cancel out. In this case, we want to cancel out "seconds" because we want to effectively replace "seconds" with "minutes" (which is what conversions are really). The numerator is the unit we want to convert to. Take care to note that sometimes you'll need multiple conversions, and sometimes it's not going to involve one conversion fraction only.
Have a look at the attached image to get a better sense of what is going on. Note the red slash marks to indicate cancellations.
Answer:
576.99
Step-by-step explanation:hope this helps;)
To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of

and the midline is a line that runs between the max and min of the y-values of the function.
Equations:f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3
A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0
D = vertical shift = midline = 3
Amplitude = 4
Find the period:
Find the midline:We know that the amplitude is 4 so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new
y-values and a range of -1 to 7. Now we need to find the midline(
the middle of our y-values) of our new range. We can find this by using the following formula
Midline:y = 3
Note, in the following equations that D = 3 = midliney = A (Bx+C) + D
y = -4 (2x + n) + 3
Also, the picture that is attached is what your equation looks like when graphed.