Find the magnetic force experienced by a proton moving with the speed of 4x10^5 m/s in the magnetic field B of magnetic 7x10^-5
T.
A- Fmagnetic = 24.8x10^-19 N
B- Fmagnetic = 34.8x10^-19 N
C- Fmagnetic = 44.8x10^-19 N
D- Fmagnetic = 54.8x10^-19 N
A- Fmagnetic = 24.8x10^-19 N
B- Fmagnetic = 34.8x10^-19 N
C- Fmagnetic = 44.8x10^-19 N
D- Fmagnetic = 54.8x10^-19 N
1 answer:
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Answer:
Explanation:
Given
Wooden board is pivoted at center and
Older child of mass is sitting at a distance of L from center
if two child of mass is sitting at a distance
and
(say) from pivot then net torque about pivot is zero
i.e.
as
Therefore
Therefore another child is sitting at a distance of