A radio frequency identification application would most likely interface with an Operational Data Store.
The Operations Data Store (ODS) is a central database that provides the latest data snapshots from multiple transaction systems for operational reporting.
It allows organizations to combine data in its original format from various sources into a single destination to provide business reporting.
ODS contains integrated updates from operational sources and supports business intelligence (BI) tools to facilitate tactical decision making.
For example, an administrator can configure ODS to pull weekly batches of data from a billing application that is rarely updated, importing individual transaction records as they occur in the sales database(thanks to these database triggers), then combine the two into new relational tables.
As a result, querying and reporting on operational data in ODS comes with the assurance that these integrated tables contain the latest and most relevant snapshots of the business.
Learn more about Operations Data Store here : brainly.com/question/14925154
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Answer:
It would be a straight line
Explanation:
On a distance-time graph, an object that moves at constant speed would be represented by a straight line.
In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:
- The speed of the object is equal to the ratio between the distance covered 
and the time taken (
):
On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:
But the variation on the y-axis (
) is equal to the distance covered (
), while the variation on the x-axis 
corresponds to the time taken (), so the slope can also be rewritten as
which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.
Answer:
0.05
Explanation:
Divide the mass of the solute by the total volume of the solution. Write out the equation C = m/V, where m is the mass of the solute and V is the total volume of the solution. Plug in the values you found for the mass and volume, and divide them to find the concentration of your solution.
