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3 years ago

What type of accidents are among the most common cause of serious work related injuries and deaths

Physics

2 answers:

Bezzdna [24]3 years ago

7 0

Trips/slips/falls are among the most common types of work related injuries and/or deaths.

eimsori [14]3 years ago

6 0

Answer:

Falls, being caught in or between objects, electrocutions, highway collision.

Explanation:

There are the following most common accident of serious work related injuries and deaths are described below by the OSHA statistics:

Falls: This is the most common accident which occurs in at the working sites. This is caused due to lack of fall protection, dangerous ladders.
Being caught in or between objects: This is caused when someone is come in between the machine or compressed and can be crushed by the machines.
Electrocutions: It is the third most common accident occur on the construction sites. It is caused by the loose wiring and by the faulty electric designs.
Highway collision: It is the leading cause of death at construction site. Vehicle collision will leads to various non fatal injuries that will affect the life of workers and their families.

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A thin film soap bubble (n=1.35) is floating in air. If the thickness of the bubble wall is 300nm, which of the following wavele

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Answer:

540 nm

Explanation:

According to the question,

The refractive index of the soap bubble, $n=1.35$ .

The thickness of the soap bubble wall is, $t=300 nm$ .

Now, for constructive interference of soap bubble.

$2nt=(m+\frac{1}{2})\lambda$ .

Now for first order m=1.

Therfore,

$\lambda =\frac{4}{3} tn$

Substitute all the variables in the above equation.

$\lambda =\frac{4}{3} (1.35)(300 nm)$ .

Therefore,

$\lambda =540 nm$ .

Therefore the visible light wavelength which is strongly reflected is 540 nm.

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3 years ago

During spring semester at MIT, residents of the parallel buildings of the East Campus dorms battle one another with large catapu

ella [17]

Answer:

The work done on the hose by the time the hose reaches its relaxed length is 776.16 Joules

Explanation:

The given spring constant of the of the spring, k = 88.0 N/m

The length by which the hose is stretched, x = 4.20 m

For the hose that obeys Hooke's law, and the principle of conservation of energy, the work done by the force from the hose is equal to the potential energy given to the hose

The elastic potential energy, P.E., of a compressed spring is given as follows;

P.E. = 1/2·k·x²

∴ The potential energy given to hose, P.E. = 1/2 × 88.0 N/m × (4.20 m)²

1/2 × 88.0 N/m × (4.20 m)² = 776.16 J

The work done on the hose = The potential energy given to hose, P.E. = 776.16 J

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2 years ago

NEED HELP NOW DUE TODAY Which of these statements is most likely correct about Newton's law on gravity? (2 points)

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_______________________a

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2 years ago

_____ is the transfer of thermal energy between two bodies which are at different temperatures. The si unit for this is the joul

ss7ja [257]

Answer:

Heat

Explanation:

The thermal energy is usually defined as a heat energy that occurs due to the increase in temperature. Due to this increasing temperature, the atoms, as well as the molecules, start to migrate at a much faster rate and rapid collisions occur with one another.

This temperature change that is involved in this process can be measured.

Thus, in thermal energy, heat (heat energy) is transferred from one body to another at different distinct temperatures.

The SI unit of heat is Joule.

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2 years ago

A 0.49-kg cord is stretched between two supports,7.3m apart. When one support is struck by a hammer, a transverse wave travels d

Wewaii [24]

Answer:

T= 5.18N

Explanation:

u = mass of chord / length of chord

u = 0.49/ 7.3

u = 0.067 kg/m

Velocity of sound waves (v) =length of chord / time taken for wave to travel

v = 7.3 / 0.83 = 8.795m/s

Tension is calculated below using the formula

T = v² * u

T = (8.795)² x 0.067

T= 5.18N

3 0

2 years ago