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Marysya12 [62]
3 years ago
7

What type of accidents are among the most common cause of serious work related injuries and deaths

Physics
2 answers:
Bezzdna [24]3 years ago
7 0
Trips/slips/falls are among the most common types of work related injuries and/or deaths.
eimsori [14]3 years ago
6 0

Answer:

Falls, being caught in or between objects, electrocutions, highway collision.

Explanation:

There are the following most common accident of serious work related injuries and deaths are described below by the OSHA statistics:

  • Falls: This is the most common accident which occurs in at the working sites. This is caused due to lack of fall protection, dangerous ladders.
  • Being caught in or between objects: This is caused when someone is come in between the machine or compressed and can be crushed by the machines.
  • Electrocutions: It is the third most common accident occur on the construction sites. It is caused by the loose wiring and by the faulty electric designs.
  • Highway collision: It is the leading cause of death at construction site. Vehicle collision will leads to various non fatal injuries that will affect the life of workers and their families.
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I think the correct answer from the choices listed above is option A. A high frequency wave is a wave with a low level of energy and a high pitch. Frequency is the number of waves passing per second of time. Hope this answers the question. 
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What is role of force on the speed of moving object? ​
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Explanation:

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What is the direction of acceleration due to gravity​
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3 years ago
A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons
torisob [31]

Answer:

0.1 s

Explanation:

The net force on the log is F - f = ma where F = force due to winch = 2850 N, f = kinetic frictional force = μmg where μ = coefficient of kinetic friction between log and ground = 0.45, m = mass of log = 300 kg and g = acceleration due to gravity = 9.8 m/s² and a = acceleration of log

So F - f = ma

F - μmg = ma

F/m - μg = a

So, substituting the values of the variables into the equation, we have

a = F/m - μg

a = 2850 N/300 kg - 0.45 × 9.8 m/s²

a = 9.5 m/s² - 4.41 m/s²

a = 5.09 m/s²

Since acceleration, a = (v - u)/t where u = initial velocity of log = 0 m/s (since it was a rest before being pulled out of the ditch), v = final velocity of log = 0.5 m/s and t = time taken for the log to reach a speed of 0.5 m/s.

So, making t subject of the formula, we have

t = (v - u)/a

substituting the values of the variables into the equation, we have

t = (v - u)/a

t = (0.5 m/s - 0 m/s)/5.09 m/s²

t = 0.5 m/s ÷ 5.09 m/s²

t = 0.098 s

t ≅ 0.1 s

6 0
3 years ago
It takes a car traveling at 18 m/s, 240 seconds to reach Chick-Fil-A from the school. Determine how far Chick-Fil-A is from the
777dan777 [17]

Answer:

The requested distance is 4320 meters

Explanation:

We can use the formula for velocity in this movement at constant velocity (v), which is defined as the quotient between the distance covered divided the time it took:

v=\frac{distance}{time}

Since we know the velocity and the time, we can solve for the distance:

\neq v=\frac{distance}{time} \\18\,\frac{m}{s}  = \frac{distance}{240\,\,s} \\distance=18\,*\,240\,\,m\\distance= 4320\,\,m

8 0
3 years ago
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