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Maurinko [17]
3 years ago
7

You are using a hand-held sound level meter to measure the intensity level of the roars produced by a lion prowling in the high

grass. To decrease the measured sound intensity level by 36.2 dB requires the lion move away from you until its distance from you has increased by what factor? g
Physics
1 answer:
lions [1.4K]3 years ago
8 0

Answer:

64.57

Explanation:

We are given that

For decreasing measured sound intensity level=36.2 dB

We have to find the  factor by which the distance increase.

Let initial distance=x

Final distance=x'

According to question

36.2=10log(\frac{x'^2}{x^2})

36.2=10log(\frac{x'}{x})^2

36.2=10\times 2log\frac{x'}{x}

log\frac{x'}{x}=\frac{36.2}{20}=1.81

\frac{x'}{x}=10^{1.81}

x'=10^{1.81}x=64.57x

Hence, the distance is increases by factor of 64.57

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A man is using a fishing rod to catch fish in figure 1.
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Answer:

Explanation:

Remark

In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.

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F = ?

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A normal mode of a closed system is an oscillation of the system in which all parts oscillate at a single frequency. In general
valentina_108 [34]

Answer:

Explanation:

(A)

The string has set of normal modes and the string is oscillating in one of its modes.

The resonant frequencies of a physical object depend on its material, structure and boundary conditions.

The free motion described by the normal modes take place at the fixed frequencies and these frequencies is called resonant frequencies.

Given below are the incorrect options about the wave in the string.

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• The wave is travelling in the -x direction

• The wave will satisfy the given boundary conditions for any arbitrary wavelength \lambda_i

• The wave does not satisfy the boundary conditions y_i(0;t)=0


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The key constraint with normal modes is that there are two spatial boundary conditions,y(0,1)=0


and y(L,t)=0

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The correct options about the wave in the string is

• The wavelength \lambda_i  can have only certain specific values if the boundary conditions are to be satisfied.

(B)

The key factors producing the normal mode is that there are two spatial boundary conditions, y_i(0;t)=0 and y_i(L;t)=0, that are satisfied only for particular value of \lambda_i  .

Given below are the incorrect options about the wave in the string.

•  A_i must be chosen so that the wave fits exactly o the string.

• Any one of  A_i or \lambda_i  or f_i  can be chosen to make the solution a normal mode.

Hence, the correct option is that the system can resonate at only certain resonance frequencies f_i and the wavelength \lambda_i  must be such that y_i(0;t) = y_i(L;t)=0


(C)

Expression for the wavelength of the various normal modes for a string is,

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Substitute 1 for n in equation (1).

\lambda_n=\frac{2L}{1}\\\\2L

When n=2 , this is the second longest wavelength mode.

Substitute 2 for n in equation (1).

\lambda_n=\frac{2L}{2}\\\\L

When n=3, this is the third longest wavelength mode.

Substitute 3 for n in equation (1).

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Therefore, the three longest wavelengths are 2L,L and \frac{2L}{3}.

(D)

Expression for the frequency of the various normal modes for a string is,

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For the case of frequency of the i^{th} normal mode the above equation becomes.

f_i=\frac{v}{\lambda_i}

Here, f_i is the frequency of the i^{th} normal mode, v is wave speed, and \lambda_i is the wavelength of i^{th} normal mode.

Therefore, the frequency of i^{th} normal mode is  f_i=\frac{v}{\lambda_i}

.

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