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3 years ago

Work out the missing numbers

Mathematics

2 answers:

s2008m [1.1K]3 years ago

7 0

Answer:

1.= -19 2. -35 3. -180 4. -81

Step-by-step explanation:

Bingel [31]3 years ago

4 0

Answer:

A -19

B -35

C -180

D-9

Step-by-step explanation:

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For the past three months, Grace used her cell phone for 43 minutes, 62 minutes, and 57 minutes how many minutes would she have

mina [271]

Answer:1

Step-by-step explanation:

Her average over those three months already is 54 so she has and average on 1 min left

8 0

3 years ago

Mark's school is selling tickets to the annual dance competition. On the first day of ticket sales the school sold 4 senior tick

erica [24]

The cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

Solution:

Let "a" be the price of each senior ticket

Let "b" be the price of each child ticket

On the first day of ticket sales the school sold 4 senior tickets and 4 child tickets for a to total of 68

Thus a equation is framed as:

4 senior tickets x price of each senior ticket + 4 child tickets x price of each child ticket = 68

$4 \times a + 4 \times b = 68$

4a + 4b = 68 ---------- eqn 1

The school took in 120 on the second day by selling 12 senior tickets and 5 child tickets

Similarly, we frame a equation as:

$12 \times a + 5 \times b = 120$

12a + 5b = 120 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

12a + 12b = 204 -------- eqn 3

Subtract eqn 2 from eqn 3

12a + 12b = 204

12a + 5b = 120

( - ) --------------

7b = 84

b = 12

Substitute b = 12 in eqn 1

4a + 4(12) = 68

4a + 48 = 68

4a = 20

a = 5

Thus cost of each senior ticket is $ 5 and cost of each child ticket is $ 12

4 0

3 years ago

The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t

Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

d = 40 - 36 so

d = 4.

That means that each duck costs $4.

3 0

4 years ago

Here is a diagram and its corresponding equation. Find the solution to the equation.

Katen [24]

4(x + 7) = 38

Since there is no operation sign between the 4 and parenthesis, it makes it an automatic multiplication problem.

You would use distributive property to multiply each which should leave your equation looking like this afterwards:

4x + 28 = 38
(4 times x and 4 times 7)

You would then solve it like a two step equation,

1. +28 - 28 = 0
2. 38 - 28 = 10

4x = 10

10 divided by 4 = 2.5

x = 2.5

We can recheck our work by substituting in the value of x.

4(2.5 + 7) = 38

10 + 28 = 38

When we substituted in the value, it gave us the correct inequality.

Therefore,
x = 2.5

5 0

2 years ago

Read 2 more answers

PLEASE HELPPPP this is my last option

mario62 [17]

Answer:

It's the first option! :)

Step-by-step explanation:

2x + 2k = m, right?

So, to bring 2k alone, we'll subtract 2x.

2k = m - 2x

Now, we'll divide both sides by 2! ^ _ ^

k = (m - 2x) / 2

That's pretty much just the (1)st option! :)

4 0

3 years ago

Read 2 more answers