Question

Given: m∠LON=77 ° m∠LOM=9x+44 ° m∠MON=6x+3 ° Find ∠MON

Answer 1

Answer:

$m\angle MON=15^o$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

$m\angle LON=m\angle LOM+m\angle MON$ ---> by addition angle postulate

substitute the given values

$77^o=(9x+44)^o+(6x+3)^o$

solve for x    

$77=(15x+47)$

$15x=77-47$                                

$15x=30\\x=2$                                                

Find the measure of angle MON  

$m\angle MON=(6x+3)^o$      

substitute the value of x        

$m\angle MON=(6(2)+3)=15^o$