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vazorg [7]
3 years ago
7

If the point (3,4) lies on the graph of the equation 3y=ax+7 ,find the value of a

Mathematics
1 answer:
Daniel [21]3 years ago
5 0

3y = ax + 7

3(4) = a(3) + 7

12 = 3a + 7

3a = 5

a = 5/3

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The critical value t* gets larger as the confidence level increases. True or false?
posledela

Answer:

We can find the critical value t_{\alpha/2}

And for this case if the confidence increase the critical value increase so then this statement is True

Step-by-step explanation:

For a confidence level given c, we can find the significance level like this:

\alpha=1 -c

And with the degrees of freedom given by:

df=n-1

We can find the critical value t_{\alpha/2}

And for this case if the confidence increase the critical value increase so then this statement is True

5 0
3 years ago
Prime factorization of 1408
V125BC [204]

Answer:

There are 7 copies of 2 and 1 copy of 11 in the product:

1408 = 2^7×11

Step-by-step explanation:

Factor the following integer:

1408

The last digit of 1408 is 8, which means it is even. Therefore 1408 is divisible by 2:

1408 = 2 704:

1408 = 2×704

The last digit of 704 is 4, which means it is even. Therefore 704 is divisible by 2:

704 = 2 352:

1408 = 2×2×352

The last digit of 352 is 2, which means it is even. Therefore 352 is divisible by 2:

352 = 2 176:

1408 = 2×2×2×176

The last digit of 176 is 6, which means it is even. Therefore 176 is divisible by 2:

176 = 2 88:

1408 = 2×2×2×2×88

The last digit of 88 is 8, which means it is even. Therefore 88 is divisible by 2:

88 = 2 44:

1408 = 2×2×2×2×2×44

The last digit of 44 is 4, which means it is even. Therefore 44 is divisible by 2:

44 = 2 22:

1408 = 2×2×2×2×2×2×22

The last digit of 22 is 2, which means it is even. Therefore 22 is divisible by 2:

22 = 2 11:

1408 = 2×2×2×2×2×2×2×11

11 is not divisible by 2 since 11 is odd and 2 is even:

1408 = 2×2×2×2×2×2×2×11 (11 is not divisible by 2)

The sum of the digits of 11 is 1 + 1 = 2, which is not divisible by 3. This means 11 is not divisible by 3:

1408 = 2×2×2×2×2×2×2×11 (11 is not divisible by 2 or 3)

The last digit of 11 is not 5 or 0, which means 11 is not divisible by 5:

1408 = 2×2×2×2×2×2×2×11 (11 is not divisible by 2, 3 or 5)

Divide 7 into 11:

| | 1 | (quotient)

7 | 1 | 1 |  

- | | 7 |  

| | 4 | (remainder)

11 is not divisible by 7:

1408 = 2×2×2×2×2×2×2×11 (11 is not divisible by 2, 3, 5 or 7)

No primes less than 11 divide into it. Therefore 11 is prime:

1408 = 2×2×2×2×2×2×2×11

There are 7 copies of 2 and 1 copy of 11 in the product:

Answer: 1408 = 2^7×11

8 0
3 years ago
HELP IM TIMED I WILL GIVE YOU BRAINLIEST!!!! The ordered pairs graphed are all equivalent ratios. What ordered pair is missing f
irina [24]

The answer is D because The ordered pairs graphed are (2,3), (6,9), and (8,12). They all have a ratio of 2 to 3. Which means each point is 2 larger on the x-axis and 3 larger on the y-axis than the previous point. The point that is missing is (4,6) since 2 + 2 = 4 and 3 + 3 = 6.

8 0
3 years ago
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If the equation of a circle is x-2 + y-6 = 4 it passes through point
Shtirlitz [24]
35 because you add 3 and 6 and that gives you 35x
6 0
3 years ago
A student is attempting to simplify the expression below. Sample mathematical work is shown. Which statement best applies to the
12345 [234]
The answer is A) The student failed to properly apply the distributive property.
4 0
3 years ago
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