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trapecia [35]
3 years ago
10

Equivalent expression -(-5.6m-n+9.9

Mathematics
1 answer:
anygoal [31]3 years ago
6 0

Answer:

5.6m + n - 9.9

Step-by-step explanation:

-(-5.6m-n+9.9)

5.6m + n - 9.9

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Find how many kilometers they traveled by
Murrr4er [49]

Answer:

Step-by-step explanation:

Biking is x and bussing is y. We know that the total distance is 325. Thus, the first equation in this system is

x + y = 325 (which says that the km traveled by bike plus the km traveled by bus totaled 325 km).

We also know that the pair biked 75 km more than they rode, giving us the second equation in our system:

x = y + 75. Now we use simple substitution and plug y + 75 in for x in the first equation:

(y + 75) + y = 325 and

2y + 75 = 325 and

2y = 250 so

y = 125 km. They rode the bus for 125 km and biked for 325 - 125 which is 200. And the difference is 75 km, as it should be!

7 0
3 years ago
A car was valued at $39,000 in the year 1995. The value depreciated to $11,000 by the year 2003.
denis23 [38]

Answer:

14.6328% , $5836.03

Step-by-step explanation:

Here we are going to use the formula

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=?

A_{8} = 11000

n=8

Hence

39000(1-r)^8 = 11000

(1-r)^8 = \frac{11000}{39000}

(1-r)^8 = 0.2820

(1-r) = 0.2820^{\frac{1}{8}

(1-r) = 0.2820^{0.125}

(1-r) = 0.8536

(1-0.8536=r

r = 0.1463

Hence r= 0.1463

In percentage form r = 14.63%

Now let us see calculate the value of car in 2003 that is after 12 years

we use the main formula again

A_{0}(1-r)^n = A_{n}

A_{0} = 39000

r=0.1463

A_{12} = ?

n=12

39000(1-0.14634)^{(12} = A_{12}

39000(0.8536)^{12} = A_{12}

39000*0.1497 = A_{12}

A_{12}=5840.34

Hence the car's value will be depreciated to $5840.34 (approx) by 2003.

5 0
3 years ago
In ∆ABC, ∠A is a right angle and m∠B = 45°. Find BC.
Oxana [17]

Answer:

22ft

Step-by-step explanation:

3 0
3 years ago
Jeff rode his bike around a bike trail 1/3 of a mile long he rode around the trail nine times write a fraction greater than 1
mr_godi [17]

ok well if Jeff rode his bike on a trail that was 1/3 of a mile and he did it nine times these is what you would do-

1/3x9=3

hope this helps

6 0
3 years ago
Find the hcf of 6 and 8 by prime factorization method <br>pls help? ​
tensa zangetsu [6.8K]

Answer:

2

Step-by-step explanation:

Factorization of the following.

6=3×2×1

8=2×2×8×1

Since, The common factor is 2.This implies that

H.C.F=2

4 0
2 years ago
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