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slega [8]
2 years ago
14

Is 3a + 3B equivalent to 3 (a + 2B) true or false​

Mathematics
2 answers:
kkurt [141]2 years ago
8 0

Answer:

False

3(a + b) ≠ 3a+6b

Step-by-step explanation:

3a + 3b \\ 3(a) + 3(b) \\ 3(a + b)

3(a + 2b) \\ 3a+3(2b) \\ 3a+6b

<h3>Hope it is helpful....</h3>
natulia [17]2 years ago
7 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

The expressions given are not equivalent.

»»————- ★ ————-««  

Here’s why:  

  • We can check if the expressions are equivalent by simplifying one of them.

⸻⸻⸻⸻

\boxed{3(a+2B)}\\\\---------\\\rightarrow3*a = 3a\\\\\rightarrow3 * 2B = 6B\\\\\text{Therefore:}\\\\3(a+2B)=\boxed{3a+6B}\\\\\text{and}\\\\\boxed{3(a+2B)\neq 3a+3B}

⸻⸻⸻⸻

  • You can also say that they are not equivalent because it was not completely distributed.

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

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Now, integrate from x = -2 to x = 1

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= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

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= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
Find the value of x shown below
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x + 61 + 61 = 180

x + 122 = 180

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Hope this helped!

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