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3 years ago

How do you simply -4•3x

1 answer:

8 0

It means you multiply 3x by -4. You could also think of it as 3x multiplied by 4 and then adding the negative. You'd get -12x

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Please can anyone help me with this I tried to do it and I got it wrong.

MatroZZZ [7]

Answer:

how do I not know it not a vires?

Step-by-step explanation:

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2 years ago

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When Rachel puts gas in her car, she records the distance that she has driven since her last

Free_Kalibri [48]

g=0.04 times d

Step-by-step explanation:

if you multiply 0.04 with every number under the d column then you’ll get the outcome of each number under g

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3 years ago

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PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

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3 years ago

Answer quick please!

Mashcka [7]

B because B is the answer

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2 years ago