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nadezda [96]
3 years ago
5

Will mark brainliest! Please show work.

Mathematics
2 answers:
Katena32 [7]3 years ago
8 0

Answer:

h(x) has the smallest minimum.

Step-by-step explanation:

f(x) = -4sin(x-0.5) + 11

y = sin(x – 0.5) has minima at y =  -1.

y = -4sin(x – 0.5) has minima at y = -4.

y = sin(x – 0.5) + 11 has minima at y = 7.

=====

According to your graph,

g(x) has a minimum at y = 6.

=====

According to your table,

h(x) has a minimum at y = 5.

Thus, h(x) has the smallest minimum.

The graph below shows the minima of f(x) at y = 7 and the minimum of h(x) at y = 5.

defon3 years ago
7 0

Answer:

h(x)

Step-by-step explanation:

You actually don't need to show that much work.

g(x) minimum is 6 due to the vertex being shown(3,6)

h(x) minimum is 5 because you can see that is it the y value on the chart

f(x) minimum is 7 ; to find this you do 11-4 = 7(Yes, it is that easy)


Thus, your resulting answer is h(x).

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What are the coordinates of the point on the directed line segment from (-6, -6)(−6,−6) to (9, -1)(9,−1) that partitions the seg
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Answer:

(0, -4)

Step-by-step explanation:

The coordinates of the points from which the directed line segment extends = (-6, -6) to (9, -1)

The ratio the required point partitions the line = 2 to 3

The formula for finding the coordinate of a point that partitions a line AB into a ratio 'a' to 'b', where the coordinates of, A = (x₁, y₁) and B = (x₂, y₂) is given as follows;

\left(\dfrac{a}{a + b} \times (x_1 - x_2)+ x_1, \ \dfrac{a}{a + b} \times (y_1 - y_2)+ y_1 \right)

Therefore, the required point is located as follows;

\left(\dfrac{2}{2 + 3} \times (9 - (-6))+ (-6), \ \dfrac{2}{2 + 3}\times (-1 - (-6))+ (-6) \right) = (0, -4)

The coordinates of the point is (0, -4)

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3 years ago
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\bf \begin{array}{ccccllll}
&distance&rate(km/hr)&time(hrs)\\
&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\
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\bf \textit{meaning}\implies 
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\\ \quad \\
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------------\\
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\\ \quad \\
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\end{cases}

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