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Kobotan [32]
3 years ago
9

Please help please guys how are you doing

Mathematics
2 answers:
andriy [413]3 years ago
7 0

Answer:

the answer of the the triangle is 6

s2008m [1.1K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

<u>First row:</u>

8 ÷ 2 = 4. → <em>Square: 4</em>

<u>Second row:</u>

14 - 4 = 10.

[two circles] = 10. So, 10÷2 = 5.

<em>Circle = 5</em>

<u>Third Row:</u>

[triangle] + 5 = 11

11 - 5 = 6

<em>Triangle = 6</em>

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Solve x TN = 8 nV =x - 2?
AleksandrR [38]

Answer:

10

Step-by-step explanation:

STUV is a parallelogram.

TV and SU are its diagonals intersecting at point N.

Diagonals of a parallelogram bisects each other.

Therefore, TN = NV

8 = x - 2

8 + 2 = x

10 = x

x = 10

7 0
3 years ago
Kevin is solving this problem. 737 × 205 What are the partial products Kevin will need to solve the problem? A. 3,685 and 147,40
Andrew [12]

the answer is A

700 x 5 = 3500

30 x 5 = 150

7 x 5 = 35

3500 + 150 +35 = 3685

700 x 200 = 140,000

30 x 200 = 6000

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140000 + 6000 + 1400 = 147400

6 0
3 years ago
A movie theater sold 2,604 tickets in 6 days. they sold the same number of tickets each day. How many tickets did the theater se
puteri [66]

Answer: The movie theater sold 434 a day

Step-by-step explanation:

How I got 434 a day

So

If you multiply 434 x 6 = 2,604

so they sold 2,604 in 6 days.

Let me know if I did something wrong.

5 0
3 years ago
2(x−4)+3x=7 solve for x
sesenic [268]

Answer:

x = 3

Step-by-step explanation:

5x - 8 + 8 = 7 + 8

5x = 15

5x/5 = 15/5

15 divided by 5 equals 3

Hope this helped you out :)

7 0
3 years ago
Read 2 more answers
Solve sin4xcos2x-cos4xsin2x=square root of 2 sinx over the interval [0,2pi)
ddd [48]
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\bf 2sin(x)cos(x)=sin(x)\sqrt{2}\implies 2sin(x)cos(x)-sin(x)\sqrt{2}=0&#10;\\\\\\&#10;sin(x)~[2cos(x)-\sqrt{2}]=0\\\\&#10;-------------------------------\\\\&#10;sin(x)=0\implies \measuredangle x=0~~,~~\pi \\\\&#10;-------------------------------\\\\&#10;2cos(x)-\sqrt{2}=0\implies 2cos(x)=\sqrt{2}\implies cos(x)=\cfrac{\sqrt{2}}{2}&#10;\\\\\\&#10;\measuredangle x=\frac{\pi }{4}~~,~~\frac{7\pi }{4}

now, we're not including the III and II quadrants, where the cosine has an angle of the same value, but is negative, because the exercise seems to be excluding the negative values of √(2).
7 0
4 years ago
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