Alright. So we know 60% is .6
And as a fraction it is 3/5. This means 38 x .6 would equal 22.8.
Hope this helps.
Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 × ![\frac{17}{60}](https://tex.z-dn.net/?f=%5Cfrac%7B17%7D%7B60%7D)
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed =
Average speed =
Average speed is 37.35 mi/h
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
its the top right answer choice
you'd simply just need to subtract 80 from 210 since its 10 per visit, and after 8 visits well its self explanatory
Step-by-step explanation:
its the top right answer choice
you'd simply just need to subtract 80 from 210 since its 10 per visit, and after 8 visits well its self explanatory