Answer:
Step-by-step explanation:
Given:

To find 
Using trigonometric relations for sums and differences of squares of the ratios.
We know:

Plugging in
in the above relation.

Subtracting both sides by 0.75.


Taking square root both sides.

∴
(Answer)
Answer:
x = 1 , y = 1 and z = 0
Step-by-step explanation:
-2x+2y+3z=0 ------(1)
-2x-y+z=-3 --------(2)
2x+3y+3z=5 ---------(3)
<u>To find the values of x,y and z</u>
(3) - (2)⇒ 2y + 4z = 2
y + 2z = 1 --------(4)
(1) - (2)⇒ 3y +2z =3 ---(5)
(5) - (4)⇒ 2y = 2
y = 1
Substituting the value of y in (4) we get z =0
Substituting the value of y and z in (1) we get x = 1
Therefore x = 1 , y = 1 and z = 0
Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)

b) Probability that exactly 2 has only cats (p=0.15)

c) Probability that exactly 1 has cats and dogs (p=0.1)

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

Answer:
110
Step-by-step explanation:
Let's define
. So when we divide it by 'x+1', we can use Bezout's Theorem which states: that any polynomial(P(X)) divided by another binomial in the form 'x - a', then the remainder will be P(a).
We can use this fact to determine the remainder, because we divided our P(X) by x + 1 which is the same as x - (-1). So we plug in P(-1).
P(-1) = (-1)^11 + 101 = -1 + 101 = 110
Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.
Explanation:
The conjecture, #angleA and angleC# allows us to write the following equation:
#angleA + angleC=180^@#
Substitute the equivalent expressions in terms of x:
#x+2+ x-2 = 180^@#
#2x = 180^@#
#x = 90^@#
From this we can compute the measures of all of the angles.
#angleA=92^@#
#angleB=100^@#
#angleC=88^@#
<span>#angleD= 80^@#</span>