Answer:
K still the same value
Step-by-step explanation:
given a reaction aA+bB<->cC+dD the constant K is defined as:

K is a constant so it won't change the value. Instead, the values of C and D are going to change. The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Answer:
81(x + 2y)(x - 2y)
Step-by-step explanation:

(6y - 11)(6y + 11) = ay
² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
100 would be correct because the 9 in the hundredths place rounds to a ten, and so does every other number.