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sp2606 [1]
2 years ago
12

∠A and \angle B∠B are supplementary angles. If m\angle A=(7x+24)^{\circ}∠A=(7x+24) ∘ and m\angle B=(7x-26)^{\circ}∠B=(7x−26) ∘ ,

then find the measure of \angle A∠A.
Mathematics
1 answer:
Arturiano [62]2 years ago
4 0

Answer:

115degrees

Step-by-step explanation:

Given the following angles

m<A=(7x+24)°

m<B=(7x-26)°

Since both angles are supplementary, their sum will be 180 degrees

Taking the sum of the angles

m<A + m<B = 180

7x+24 + 7x - 26 = 180

14x - 2 = 180

14x = 180+2

14x = 182

x = 182/14

x = 13

get m<A

m<A = 7x+24

m<A = 7(13) + 24

m<A = 91 + 24

m<A  = 115

Hence the measure of angle m<A is 115degrees

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Answer:

5b +30

Step-by-step explanation:

5 · 6 = 30

5 · b = 5b

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3 years ago
Give A={a,b,c},how many subsets does A have including 0?
Tems11 [23]
Answer: 8 subsets

----------------------------------------------------------------------
----------------------------------------------------------------------

There are n = 3 elements in the given set, so there are 2^n = 2^3 = 2*2*2 = 8 subsets. Those 8 subsets are listed below

{a,b,c}
{a,b}, {a,c}, {b, c}
{a}, {b}, {c}
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The first row is the original set. Any set is a subset of itself.
The second row represents subsets with exactly 2 elements.
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8 0
3 years ago
My question is in the image
Alecsey [184]

Answer:

13.2 miles

Step-by-step explanation:

To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.

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81 + b² = 225

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Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).

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2 years ago
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Answer:

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Step-by-step explanation:

6 0
2 years ago
The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
2 years ago
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