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Lisa [10]
3 years ago
6

3. Which of the following represent an exponential DECAY function? Select all that apply. Please hurry thank you​

Mathematics
1 answer:
Ilya [14]3 years ago
5 0
Option 2 - it is decreasing
You might be interested in
Which expression uses the associative property to make it easier to evaluate? (50points)
Naily [24]

The correct answer is option 4: (8.\frac{1}{4}).\frac{3}{5}

Step-by-step explanation:

Given expression is:

8.(\frac{1}{4}.\frac{3}{5})

The associative property states that for any three terms that are being multiplied, different order of multiplication (i.e. which two terms are multiplied first) will give the same answer.

Let a,b and c be the three terms

then

a.(b.c) = (a.b).c

So applying the associative property on given expression

8.(\frac{1}{4}.\frac{3}{5}) = (8.\frac{1}{4}).\frac{3}{5}

Hence,

The correct answer is option 4: (8.\frac{1}{4}).\frac{3}{5}

Keywords: Associative property, Properties

Learn more about associative property at:

  • brainly.com/question/9729310
  • brainly.com/question/9738996

#learnwithBrainly

5 0
3 years ago
Matt has 5 cookies Addie eats 3. How old is Addie?
Maru [420]
Old enough for Matt to seek vengeance against her
3 0
2 years ago
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-3,-7 reflected over the x axis
Aleks [24]

Answer:

The reflected point would be (3,-7)

7 0
3 years ago
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Please help it is due today
just olya [345]

i think answer is 8in2

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8 0
2 years ago
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Solve 2x^2 + x - 4 = 0 <br> X2 +
damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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