3 years ago

I need help with 11.

Mathematics

1 answer:

ioda3 years ago

3 0

Answer:

Step-by-step explanation:

last one

You might be interested in

A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat,

Paraphin [41]

Answer:

3/7.

Step-by-step explanation:

The total number of ways to pick 4 out of 8 = 8C4

= 8!/ 4!4!

= 70 ways.

The number of ways when 2 are women = 5C2 * 3

= 10 * 3

= 30.

So the required probability = 30/70

= 3/7.

6 0

4 years ago

4(x−2+y) It's for khan academy

inessss [21]

The answer is 4x-8+4y i think?

4 0

3 years ago

1.01x10^4 decimal notation

marshall27 [118]

$1.01\times10^4=1.01\times10,000=1\underbrace{0100}_{4\to}=10,100$

Answer:

1.01 × 10⁴ - scientific notation

10,100 - decimal notation

4 0

3 years ago

(1/4)^3z-1 =16^z+2*64^z-2 Z=___ Please help

wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

$(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274$

Hence, the value of Z = 0.198877274

8 0

3 years ago

Read 2 more answers

Please help no fake answers or links please

Tems11 [23]

D none of them fit the data set.

7 0

3 years ago

Read 2 more answers