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otez555 [7]
3 years ago
15

6) Find the difference of (4x - 5) and (6x + 8)

Mathematics
2 answers:
lesya [120]3 years ago
8 0

Answer:

- 2 - 13

Step-by-step explanation:

( 4 x - 5 ) - ( 6 x + 8 )

= 4 x - 5 - 6 x + 8

Arranging like terms together

= 4 x - 6 x - 5 - 8

= - 2 x - 13

Allushta [10]3 years ago
6 0

Answer:

-2x- 13

Step-by-step explanation:

Hi there!

(4x - 5)-(6x + 8)

Open up the parentheses

4x - 5-6x - 8

Combine like terms

4x -6x- 5 - 8\\-2x- 13

I hope this helps!

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A sweater us on sale for $16, which is 80% of the original price. What is the original price of the sweater?
slavikrds [6]

Answer:

$28.80

Step-by-step explanation:

16 times 0.8 = 12.8 + 16 = 28.80

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A number cube is rolled. What is the probability that a number greater than 4 will be rolled?
jek_recluse [69]

Answer:

1/6

Step-by-step explanation:

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2 years ago
What is the sum of the series? 4 ∑k=1 (2k^2−4)
larisa86 [58]

The sum of the series \sum_{k=1}^{4}\left(2 k^{2}-4\right) is 44.

Step-by-step explanation:

The given series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

To find the sum of the series, we need to substitute the values for k in the series.

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]

Now, simplifying the square terms, we get,

[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]

Multiplying the terms,

[2-4]+[8-4]+[18-4]+[32-4]

Subtracting the values within the bracket term, we get,

-2+4+14+28

Now, adding all the terms, we get the sum of the series,

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

Thus, the sum of the series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

8 0
3 years ago
Find the greatest possible number of consecutive zeros at the end of the product of three positive integers if the sum of these
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Answer:

A. Of first 100 multiples of 10

B. 5*10*15*20*25*30*35*40*40*45

C. 100!

I would also like to know whether this kind of question is possible in GMAT and what would be the complexity level.

1. 124

2. 10

3. 24

6 0
2 years ago
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