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Vesnalui [34]
2 years ago
14

What is the area of the parallelogram shown above

Mathematics
1 answer:
adoni [48]2 years ago
8 0

The area of the parallelogram is 55 square feet

<h3>How to determine the area of the parallelogram?</h3>

From the figure, we have the following dimensions:

Height = 5 ft

Base = 11 ft

The area of the parallelogram is calculated as:

Area = Base * Height

This gives

Area = 5ft * 11ft

Evaluate the product

Area = 55 square feet

Hence, the area of the parallelogram is 55 square feet

Read more about areas at:

brainly.com/question/76387

#SPJ1

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1/2 is the probability the coin would land heads up both times.
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What Is the solution to the above system of equations? 2x+3y=11
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A sample of gold has a mass of 579 g. The volume of the sample is 30 cm3. What is the density of the gold sample?
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The density of the gold sample is 19.3g/cm³

Let the mass of the gold sample be represented by m

m = 579 g

Let the volume of the gold sample be represented by V

V = 30 cm³

Let the density of the gold sample be represented by ρ

The formula for the density is:

Density = \frac{Mass}{Volume}

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3 0
3 years ago
A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long
Pie

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

                                                          = 3 \times 20 = 60 inches

Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

                                                 =\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}  square inches.

Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

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