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andre [41]
3 years ago
14

Please answer this question!

Mathematics
2 answers:
Archy [21]3 years ago
7 0

Answer:

the answer is 45 . so circle 4

ZanzabumX [31]3 years ago
5 0

Answer:

<em>(4) y = 45</em>

Step-by-step explanation:

\frac{y}{5}  - 2 = 7\\\frac{y}{5} = 7 + 2\\\frac{y}{5}  = 9\\y = 9 (5)\\y =45

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Answer:

table B

every other input and output has the same number in a table

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Answer:

Step-by-step explanation:

For a number to be divisible by 4 you just need to worry about the 10s and 1s place.  You also want to know that the 1s cylce every 20, or in other words:

4 8 12 16 20

24 28 32 36 40 and so on.  So the only numbers that x can be there are 1, 3, 5, 7, 9.  Does that make sense?  and can you manage  the rest?

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Brahmagupta solved a quadratic equation of the form ax2 + bx = c using the formula x=V
Hatshy [7]

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Step-by-step explanation:

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Find the measure of the indicated angle to the nearest degree​
sweet-ann [11.9K]

Answer:

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Step-by-step explanation:

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5 0
2 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.​
Leni [432]

Answer:

To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;

3·4ⁿ is divisible by 3 and 51 is divisible by 3

Where we have;

S_{(n)} =  3·4ⁿ + 51

S_{(n+1)} = 3·4ⁿ⁺¹ + 51

S_{(n+1)} - S_{(n)} = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ

S_{(n+1)} - S_{(n)} = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ

∴ S_{(n+1)} - S_{(n)} is divisible by 9

Given that we have for S₀ =  3×4⁰ + 51 = 63 = 9×7

∴ S₀ is divisible by 9

Since  S_{(n+1)} - S_{(n)} is divisible by 9, we have;

S_{(0+1)} - S_{(0)} =  S_{(1)} - S_{(0)} is divisible by 9

Therefore S_{(1)} is divisible by 9 and S_{(n)}  is divisible by 9 for all positive integers n

Step-by-step explanation:

5 0
3 years ago
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