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Rudiy27
3 years ago
7

1. How many lines are there in the figure?

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer: Looking for the same thing answer!!

Step-by-step explanation:

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PLEASE HELP IF YOU KNOW THE ANSWERS
vesna_86 [32]
.1 = 1/10

.16_6 = 1/6

0.6_6 = 2/3

0.6 = 3/5
8 0
3 years ago
Read 2 more answers
last free brainliest, would mean a lot if u do something to help me gain more points so i give more free brainliests! ty love u
beks73 [17]
Ok. Thanks for the free brainliest
7 0
3 years ago
WORTH BRAINLIST!!!!!!
Sladkaya [172]

Sum : (5 x+1)

Term : 1, 5x and 3y

Product : 9(5x+1),5x and 3y

Factor : 5 and x, 3 and y, 9 and 5x+1

Quotient : \frac{9(5x+1)}{3y}

Coefficient : 5 is the coefficient of x and 3 is the coefficient of y.

Explanation:

The expression is \frac{9(5x+1)}{3y}

Sum: Sum is the result of addition of terms.

Thus, from the expression,

Sum = (5 x+1)

Term : A term is a single number or a variable or a number multiplied with a variable.

Thus, from the expression,

Term = 1, 5x and 3y

Product : Product is the result of multiplication of numbers.

Thus, from the expression,

Product = 9(5x+1),5x and 3y

Factor : The numbers that are multiplied is called a factor.

Thus, from the expression,

Factor = 5 and x, 3 and y, 9 and 5x+1

Quotient : Quotient is the result of dividing two numbers or variables.

Thus, the given whole expression is a quotient.

Hence, Quotient = \frac{9(5x+1)}{3y}

Coefficient : Coefficient of a variable is a number multiplied with a variable.

Thus, from the expression,

Coefficient : 5 is the coefficient of x and 3 is the coefficient of y.

3 0
3 years ago
Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}
Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

f(A) = \{x^2  \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2  \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4]  = f(A \cap B)\\

Therefore it is true for intersection. Now for union, we have that

A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]

Therefore, for this case, it would be true that f(A\cup B) = f(A)\cup f(B).

(b)

1 is not a set.

(c)

To begin with  

A\cap B \subset A,B

Therefore

g(A\cap B) \subset g(A) \cap g(B)

Now, given an element of g(A) \cap g(B) it will belong to both sets, therefore it also belongs to g(A\cap B), and you would have that

g(A)\cap g(B) \subset  g(A \cap B), therefore  g(A)\cap g(B)  =  g(A \cap B).

(d)

To begin with A,B  \subset A \cup B, therefore

g(A) \cup g(b) \subset g(A\cup B)

7 0
3 years ago
I need help please (brainllest)
Ksenya-84 [330]

Answer:

-3 -13

0 -4

3 -1

6 14

///

-3 17

0 11

1 9

3 5

6 -1

Step-by-step explanation:

7 0
3 years ago
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