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2 years ago

13

In a bag of mini candy bars, 40% of the candy bars are Snickers. There are 120 Snickers in the bag. How many total mini candy ba

rs are in the bag?

1 answer:

bixtya [17]2 years ago

7 0

Answer:

The amswer is 48.

Step-by-step explanation:

120×0.40=48

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URGENT NEEDS TO ME SUBMITTED BY MIDNIGHT!! The ratio of girls to boys in Mr. Hansen’s class is 4:5. The ratio of girls to boys i

nadya68 [22]

If the ratio of girls to boys in Mr. Hansen's class is 4:5, and the ratio of girls to boys in Ms. Luna's class is 8:10, then the equation that correctly compares the ratio of both Mr. Hansen's class and Ms. Luna's class are 4/5 = 8/10.

3 0

3 years ago

Solve this equation:<br> X – 8<br> 6<br> = 4.5<br> Your answer

barxatty [35]

Answer:

Multiply by 6 on both sides

X-8 = 27

add 8 to both sides

X = 35

Hope this helps

Double-checking

35 - 8 = 27

27 / 6 = 4.5

35 = X is the answer

Hope this helps

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don

Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

$nP_r=\frac{n!}{(n-r)!}$

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

$\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}$

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

$_nC_r=\frac{n!}{(n-r)!r!}$

The formula can now be applied as follows;

$\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}$

If the order is not relevant, then the selection can be done in 56 ways.

3 0

11 months ago

The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than

k0ka [10]

Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

$x + 5*y + 10*z = 227$

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

$y = z + 6\\x = 2 + 24*z$

Applying these values on the first equation, we have:

$2 + 24*z + 5*(z + 6) + 10*z = 227\\2 + 24*z + 5*z + 30 + 10*z = 227\\39*z + 32 = 227\\39*z = 227 - 32\\39*z = 195\\z = \frac{195}{39}\\z = 5$

Applying z to the formulas of y and x, we have:

$y = 5 + 6 = 11\\x = 2 + 24*5 = 122$

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

4 0

3 years ago

Stephan has a piece of wood that measures 18 inches long and 12 inches wide. He wants to make a tray with sides 2 inches high. M

valkas [14]

Answer:

i. No, Maurice statement is wrong.

ii. Stephan does not have sufficient pieces of wood to make the tray because the square inches required is more than what he has.

Step-by-step explanation:

Stephan's piece of wood measures; 18 inches in length and 12 inches in width.

Since the piece of wood has a shape of a rectangle,

the area of the piece of wood = length × width

= 18 × 12

= 216 square inches

According to Maurice's statement, he could make a tray that has a base of 1012 inches by 1012 inches.

The base has the shape of a square, so that;

the area of the base = length × width = $length^{2}$

= 1012 ×1012

= 1024144 squared inches

This shows that Stephan does not have sufficient wood to make the tray because the square inches required is more than what he has.

5 0

3 years ago