I am about to get my homework done I just need these two. (Thank you if you answer!!)

Mathematics

1 answer:

AnnZ [28]2 years ago

8 0

Answer:

$-7=h\\-6.81=q$

Step-by-step explanation:

For question #1:

$-3=h+8/2\\-3=h+4\\-7=h$

For question #2:

$q+16.41=9.6\\q=-6.81$

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Determine the next three terms in the following sequence

tia_tia [17]

Answer:

Step-by-step explanation:

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3 years ago

Suppose we want to choose 5 colors, without replacement, from 8 distinct colors.1. If the order is relevant, how many can be don

Charra [1.4K]

(1) From the information given, if we want to choose 5 colors from 8 distinct colors and the order in which the selection is made is relevant, then what we have is a permutation.

The formula is given as;

$nP_r=\frac{n!}{(n-r)!}$

This formula means we need to select/arrange r items out of a total of n items and the anwer derived would be the total number of arrangements possible.

Therefore, we would have;

$\begin{gathered} nP_r\Rightarrow_8P_5 \\ _8P_5=\frac{8!}{(8-5)!}\Rightarrow\frac{8!}{3!} \\ _8P_5=\frac{8\times7\times6\times\ldots1}{3\times2\times1}\Rightarrow\frac{40320}{6} \\ _8P_5=6720 \end{gathered}$

Therefore, if the order is relevant, this selection can be done in 6,720 ways.

(2) If the order is NOT relevant, then what we need to calculate is a combination and the formula is;

$_nC_r=\frac{n!}{(n-r)!r!}$

The formula can now be applied as follows;

$\begin{gathered} _nC_r\Rightarrow_8C_5 \\ _8C_5=\frac{8!}{(8-5)!\times5!} \\ _8C_5=\frac{8!}{3!\times5!}\Rightarrow\frac{8\times7\times6\times\ldots1}{(3\times2\times1)\times(5\times4\times\ldots1)} \\ _8C_5=\frac{40320}{6\times120} \\ _8C_5=56 \end{gathered}$

If the order is not relevant, then the selection can be done in 56 ways.

3 0

1 year ago

Maddie tried to divide 160 stickers equally amongst herself and 5 friends. There was some stickers left over, so she kept them.

Nutka1998 [239]

Answer:

well you just get 32

Step-by-step explanation:

but i divide 16 divide 5 and got 3.2 so it might be an extra .2 stickers

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3 years ago

I don't know how to simplify