The fraction would be 37 out of 42. You basically divide the two and get something around 88%.
2.4<7
2.4 / 0.6 = 4
2.4 / 2.4 = 1
4.8<7
4.8 / 0.6 = 8
4.8 / 2.4 = 2
Answer:
The probability that a person with restless leg syndrome has fibromyalgia is 0.183.
Step-by-step explanation:
Denote the events as follows:
<em>F</em> = a person with fibromyalgia
<em>R</em> = a person having restless leg syndrome
The information provided is as follows:
P (R | F) = 0.33
P (R | F') = 0.03
P (F) = 0.02
Consider the tree diagram attached below.
Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:


Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.
Answer:
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